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777dan777 [17]
3 years ago
7

Praveen wants to make an array to help solve the problem 179 ÷ 6. How should he do it?

Mathematics
1 answer:
anzhelika [568]3 years ago
7 0

Answer:

divide

Step-by-step explanation:

egjk5rydurbock d copy dyfjdigi

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The temperature in Yarmouth is 6.5 C. In Sydney it is 8C colder. What is the
lukranit [14]
If Yarmouth is 6.5C and Sydney is 8C colder you would just subtract.
6.5-8=-1.5C
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3 years ago
(-14x+14)1/2+14x use distributive property <br> Help please
brilliants [131]

1/2(-14x + 14) + 14x

<em><u>Distributive property.</u></em>

-7x + 7 + 14x

<em><u>Combine like terms.</u></em>

7x + 7 (This is the simplified answer.)

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4 years ago
Multiply (4a-2)(a+7)
kipiarov [429]

When multiplying binomials, one takes the first binomial and multiply each term by the first term of the second binomial, and then you do the same with the second term of the  second binomial, to obtain:

4a^2+14a-2a-14

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3 years ago
Help volume of a cone!!!!
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7 0
3 years ago
Given that sectheta = -37/12 what is the value of cottheta for pi/2 &lt; theta&lt; pi?
lys-0071 [83]

Answer:

cotg(\theta) = -\frac{12}{35}

Step-by-step explanation:

The cotangent of theta is:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

sec(\theta) = \frac{1}{\cos{\theta}}

In this question

sec(\theta) = -\frac{37}{12}

So

-\frac{37}{12} = \frac{1}{\cos{\theta}}

Using cross multiplication

-37\cos{\theta} = 12

37\cos{\theta} = -12

\cos{\theta} = -\frac{12}{37}

Now we apply the following trigonometric identity:

\sin{\theta}^{2} + \cos{\theta}^{2} = 1

\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1

\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}

\sin{\theta}^{2} = 1 - \frac{144}{1369}

\sin{\theta}^{2} = \frac{1369 - 144}{1369}

\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}

Since the angle is in the second quadrant, the sine is positive.

\sin{\theta} = \frac{35}{37}

Finally, the cotangent:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}

cotg(\theta) = -\frac{12}{35}

4 0
4 years ago
Read 2 more answers
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