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erma4kov [3.2K]
2 years ago
12

Determine all the zeros of p(x)=x^4-9x^2+20

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

Answer:

ANSWER

Real roots

x=5

x=7

Complex roots

x=2+3–√i≈2.0+1.73205080756888i

x=2−3–√i≈2.0−1.73205080756888i

Step-by-step explanation:

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Help help help! Im stuck please help!
ioda

Answer:

1) 8/15

Step-by-step explanation:

When dividing by a number, multiply by its reciprocal.

2/5 ÷ 3/4

2/5 × 4/3

8/15

8 0
3 years ago
50/100 in tenth fraction and decimal form
Flura [38]

Answer:

5/10 and .5

Step-by-step explanation:

50/100 is 1/2 so 1/2 is equal to 5/10

5/10 is also 1/2 and 1/2 as a decimal is .5 or 0.5

hope it helps !

7 0
2 years ago
To solve the equation 2−5(3+4x)=2x+7, Miranda's first step was to write 2−15−20x=2x+7. Which property did Miranda use in her fir
Aneli [31]

Answer:

Step-by-step explanation:

distributive

3 0
3 years ago
- The four-digit number 1210 has an interesting property.
vampirchik [111]

Answer:

ABCDEFG = 3211000

Step-by-step explanation:

A counts the number of zeroes, and there are 3 zeroes (E, F, G), so A = 3.B counts the number of ones, and there are 2 ones (C, D), so B = 2.C counts the number of twos, and there is 1 two (B), so C = 1.D counts the number of threes, and there is 1 three (A), so D = 1.There is no four, five, six in, so E, F, G are all zeroes.

5 0
2 years ago
Who Washes? Erica and Aaron, who are siblings, have decided to use a lottery system to decide who will wash dishes every night.
Anestetic [448]

Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.

They put some red and blue power chips and draw each one.  If same colour, Aaron will wash and if not same colours Erica will wash

If the game is to be fair, then both should have equal chances of opportunity for washing.

i.e. Probability for Erica washing = Prob of Aaron washing

i.e. P(different chips) = P(same colour chips)

Say there are m red colours and n blue colours.

Both are drawing at the same time.

Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2

Probfor different colour = mC1+nC1/(m+n)C2

The two would be equal is mC2 +nC2 = m+n

This is possible if mC2 =m and nC2 = n.

Or m = 2+1 =3 and n =3

That for a fair game we must have both colours to be 3.


3 0
3 years ago
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