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kicyunya [14]
3 years ago
7

Whet is 2y+14x-7x+9y

Mathematics
2 answers:
Gekata [30.6K]3 years ago
7 0

Answer:

11y+7x

Step-by-step explanation:

because you combine like terms which is 14x - 7x which is 7X and 9y plus 2y which is 11y so 11y plus 7x is the answer

matrenka [14]3 years ago
6 0

Answer:

Step-by-step explanation:

2y + 14x - 7x + 9y

2y + 9y + 14x - 7x

11y + 7x

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N/4 -14=10<br> what is n?
mrs_skeptik [129]

Answer:

n=96

Step-by-step explanation:

3 0
3 years ago
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The mass of the eggs laid by a certain breed of hen is a normally distributed random variable with mean 0.06kg and standard devi
Olin [163]

a (i) The number of standard size is 288 eggs

a (ii) The number of medium size is 1,476 eggs

a (iii) The number of large size is 36 eggs

b (i) The expected profit made from selling the standard size is Gh¢43.2

b (ii) The expected profit made from selling the medium size is Gh¢516.6

b (iii) The expected profit made from selling the large size is Gh¢16.2

The given parameters:

the mean of the distribution, m = 0.06 kg

standard deviation (std) of the distribution, d = 0.009 kg

number of the samples, n = 1800 eggs

(i) Find the position of "less than 0.052 kg (standard size)":

  • 1 standard deviation below the mean = m - d
  • m - d = 0.06 kg  -  0.009 kg = 0.051 kg

(<em>the </em><em>standard size</em><em> is 1 standard deviation below the mean</em>)

  • less than 1 standard deviation below the mean in a normal distribution is equal to 16% of the data samples
  • Number of standard size = 0.16 x 1800 = 288 eggs

(ii) Find the position of "Between 0.052 kg and 0.075kg (medium size)":

  • 0.052 kg is 1 standard deviation below the mean
  • 2 standard deviation above the mean = m + 2d
  • m + 2d = 0.06 + 2(0.009) = 0.078 kg

(<em>the </em><em>medium size</em><em> is between 1 std below the mean and 2 std above the mean</em>)

  • Between 1 std below the mean and 2 std above the mean in a normal distribution = (68 + 14)% = 82%
  • Number of medium size = 0.82 x 1800 = 1,476 eggs

(iii) Find the position of "Greater than 0.075 kg (large size)":

  • 0.078 kg is 2 standard deviation below the mean
  • greater than 2 std above the mean in a normal distribution = 2 % of the data samples
  • Number of large size = 0.02 x 1800 = 36 eggs

<u>Check:</u> <em>288 eggs + 1476 eggs + 36 eggs = 1,800 eggs</em>

(b) the cost of production of an egg = Gh¢0.45

the selling price of the standard size = Gh¢0.60

the selling price of the medium size = Gh¢0.80

the selling price of the large size = Gh¢0.95

(i) The expected profit made from selling the standard size:

Profit = total revenue - cost of production

Profit = 288(0.6) - 288(0.45) = Gh¢43.2

(ii) The expected profit made from selling the medium size:

Profit = total revenue - cost of production

Profit = 1476(0.8) - 1476(0.45) = Gh¢516.6

(iii) The expected profit made from selling the large size:

Profit = total revenue - cost of production

Profit = 36(0.9) - 36(0.45) = Gh¢16.2

Learn more here: brainly.com/question/22520030

3 0
3 years ago
Please i need help its for a grade
horsena [70]
The answer is 25 and make sure it’s correct
8 0
3 years ago
In a random sample of 8 ​people, the mean commute time to work was 35.5 minutes and the standard deviation was 7.4 minutes. A 90
konstantin123 [22]

Answer:

Margin of Error = 5.4088 ;

Confidence interval = (30.1 ; 40.9)

Interval estimate are almost the same

Step-by-step explanation:

Given that :

Population standard deviation, σ = 9.3

Sample size, n = 8

Xbar = 35.5

Confidence level = 90%

The confidence interval:

Xbar ± Margin of error

Margin of Error = Zcritical * σ/sqrt(n)

Zcritical at 90% = 1.645

Margin of Error = 1.645 * 9.3/sqrt(8) = 5.4088

Confidence interval :

Xbar ± Margin of error

35.5 ± 5.4088

Lower boundary = (35.5 - 5.4088) = 30.0912 = 30.1

Upper boundary = (35.5 + 5.4088) = 40.9088 = 40.9

(30.1 ; 40.9)

T distribution =. (30.5 ; 40.5)

Normal distribution = (30.1, 40.9)

4 0
3 years ago
Please NO LINKS <br> ONLY CORRECT ANS
forsale [732]

Answer:

D

Step-by-step explanation:

just cross multiply

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