Answer:
b 78
Step-by-step explanation:
because the area is what you get
in the equation
b 78
If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show
Let 
. Compute the inverse:
![f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20%5Csqrt%7B1%20%2B%20f%5E%7B-1%7D%28x%29%5E3%7D%20%3D%20x%20%5Cimplies%20f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%5E2-1%7D)
and we immediately notice that ![f^{-1}(x+1)=\sqrt[3]{x^2+2x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%2B1%29%3D%5Csqrt%5B3%5D%7Bx%5E2%2B2x%7D)
.
So, we can write the given integral as
Splitting up terms and replacing 
in the first integral, we get
Answer:
52.4
Step-by-step explanation:
Arc length = 2πr(θ/360)
r = 10
θ = 300°
Arc length = 2π(10)(300/360) = 20π(0.8333) = 16.666π ≈ 52.36
Answer:
The Answer is C
Step-by-step explanation:
Look at each coefficient next to the degree of the radical. When inputting that number for synthetic division (From greatest degree to least) you would get 8 1 and -5. The number that is the divisor is the 6, but you have to set (x - 6) to equal zero, which would get you a number of 6.
