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shusha [124]
3 years ago
6

How many pieces of ribbon can you cut from 10 meters, if each piece is 4cm long?​

Mathematics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

answer:250 pieces

1 metre=100cm so

10metres =100*10 =1000cm

each piece is 4 CM long, so.,

no. of pieces=1000/4

by dividing by 2....

=500/4

again by dividing by2...

=250/1=250 pieces

so 250 pieces of ribbon can be cuttted from 10 metre long ribbon.

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May someone please help me out on this question
NISA [10]

Answer:

A

Step-by-step explanation:

It's hard to see but when x is 6, y is 4.5. Just plug that into each equation and see which one is correct.

x^{2} =8y\\x=6;y=4.5\\6^{2} =8(4.5)\\36=36

8 0
3 years ago
1/4x – 2 = 3/8 Please show an equation and work. :)
Julli [10]
1/4x - 2 = 3/8

First, to start solving this, we can rearrange our fraction. Let's take 1/4x and change it to x/4. Why? Well, a variable can also be considered as the number 1.
\frac{x}{4} - 2 =  \frac{3}{8}

Second, now we can continue solving for our variable (x). Let's add 2 to each side.
\frac{x}{4} =  \frac{3}{8} + 2

Third, let's simplify 3/8 + 2. (3/8 + 2 = 2.375 =19/8)
\frac{x}{4} =  \frac{19}{8}

Fourth, continue trying to get the variable by itself. Multiply each side by 4.
x =  \frac{19}{8} \times 4

Fifth, let's simplify 19/8 × 4. This is simple. Leave the denominator be and just do 19 × 4, which equals 76.
x =  \frac{76}{8}

Sixth, our final step is to simplify our fraction. To do so, we will need to list the factors of the numerator and denominator and find the greatest common factor (GCF).

Factors of 76: 1, 2, 4, 19, 38, 76
Factors of 8: 1, 2, 4, 8

Since 4 is our first common factor, it is considered our GCF.

Seventh, now let's divide. Divide both the numerator and denominator by the GCF (4) to create our new simplified fraction.
76 \div 4 = 19 \\ 8 \div 4 = 2

Answer in fraction form: \fbox {x = 19/2}
Answer in decimal form: \fbox {x = 9.5}
8 0
3 years ago
The side of a square is 2^7/2. Using the area formula A = s^2, determine the area of the square.
sergij07 [2.7K]
The answer is 49 square inches?

5 0
3 years ago
Read 2 more answers
One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}

And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

5 0
3 years ago
9^y-3=8<br><br> JUST DO IT!<br> PLZ...
aleksley [76]
Hello My Dear Friend!

9^y-3=8<span>
We move all terms to the left:
</span>9^y-3-(8)=0<span>
We add all the numbers together, and all the variables
</span>9^y-11=0<span>
We move all terms containing y to the left, all other terms to the right
</span>9^y=11
y=11/1
y=11

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

(Ps. Mark As Brainliest IF Helped!)

<span>-UniteTheLeague, Justice League!!! :D</span>
7 0
3 years ago
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