There are 11 parts of fruit: 4-strawberry, 3- grape, 2, cherry, 1- apple, 1-orange
4/11 from the entine quantity of fruits- strawberry
3/11-grapes
2/11- cherries
1/11- apples
1/11- oranges } ⇒ the quantity of oranges and apples are equal
The biggest part of the fruit- 4/11 - are strawberries
4/11>3/11>2/11>1/11
the smallest part of the fruit- apples and oranges
11 kilograms of the same dog food costs $69.85.
Step-by-step explanation:
Step 1:
Paris buys 18 kg of dog food for $114.30. The food can be purchased in 1 kg bags.
If she bought the 18 kg of dog food with 1 kg bags, she would have had to buy 18 such bags.
So we need to calculate the cost of a 1 kg bag.
If 18 bags cost $114.30 we divide it by 18 to calculate the cost of 1kg.
The cost of a 1 kg bad
So a 1 kg bag of dog food costs $6.35.
Step 2:
To calculate the cost of 11 kg of the same dog food, we multiply the cost of a single bag with the number of bags.
If she were to buy the 11 kg through 1 kg bags, she would need to buy 11 such bags.
The cost of 11 kg of dog food
So 11 kg of dog food would cost $69.85.
Answer:
no she is not correct
just because it ends in 7 does not mean that it is prime
Step-by-step explanation:
57 is divisible by 1, 3, 17, and 57
67 is a prime number and is only divisible by 1 and itself
a thanks would be appreciated
Answer:The b is 15.7-2(a)
Step-by-step explanation:
2a+b=15.7
b=15.7-2a
The length will be a+a which is greater than length of b
The b is 15.7-2(a)