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Oksi-84 [34.3K]
3 years ago
11

Which linear inequality is represented by the graph?

Mathematics
1 answer:
pantera1 [17]3 years ago
7 0

Answer:

Wow

Step-by-step explanation:

I love the question pls i also want to know the answer to it

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Answer:

i dont under stand sorry i cant help sorry

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How many perfect cubes are there between 2 to 200 ?<br> ANSWER fast
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Answer:

Three

Step-by-step explanation:

The perfect cubes between 2 to 200 are

{3}^{3}  = 27 \\  \\  {4}^{3}  = 64 \\  \\  {5}^{3}  = 125 \\

Hence, there are only three perfect cubes 27, 64 and 125 between 2 to 200.

3 0
3 years ago
3x = 1/9 what is x<br> Please respond quick
SOVA2 [1]
X=1/27 decimal form=0.037 repeating
3 0
2 years ago
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Answer this please. Give a great answer
Flura [38]

Answer:

275

Step-by-step explanation:

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3 years ago
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20. Based on student records, 25% of the students at a large high school have a
Elenna [48]

Answer:

(E) 0.71

Step-by-step explanation:

Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.

So, the  probability that the student has a GPA lower than 3.5 and is not taking any AP  classes is calculated as:

P(A'∩B') = 1 - P(A∪B)

it means that the students that have a GPA lower than 3.5 and are not taking any AP  classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.

Therefore, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled  in at least one AP class is 0.12

So, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 0.25 + 0.16 - 0.12

P(A∪B) = 0.29

Finally, P(A'∩B') is equal to:

P(A'∩B') = 1 - P(A∪B)

P(A'∩B') = 1 - 0.29

P(A'∩B') = 0.71

5 0
3 years ago
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