The value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.
<h3>What is the rate of speed?</h3>
The rate of speed is the rate at which the total distance is travelled in the time taken. Rate of speed can be given as,
r=d/t
Here, (d) is the distance travelled by the object and (t) is time taken but the object to cover that distance.
The train traveled 1/3 of the distance at 30 mph and the remaining distance at 40 mph. Let <em>t</em> is the time the train has taken to travel and x is the distance it travelled. Thus,

After two hour a car left the same station traveled the first 3 hours at 35 mph and the remaining distance at 51 mph. Let <em>t</em> is the time the car has taken to travel and x is the distance it travelled. Thus,

As t is same, thus put the value of t in this equation,

Thus, the value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.
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Answer:
d) 135º
Step-by-step explanation:
Note that the angle DCU is the sum of the angles DCB and BCU. The angle DCB is 90º because A B C D is a square, then all its angles are equal to 90º.
After attaching B U C to A B C D, we obtain a trapezoid A U C D. Since A U C D has at least one pair of parallel sides, then AU should be parallel to CD, thus the angle CBU must be 90º.
B U C is isoceles, so we conclude that other two angles must have the same size, and due to the sum of the angles of a triangle being 180º, then both BUC and BCU are equal to 45º
As a result, the angle DCU is equal to 90º+45º = 135º. Option d is the correct one.
Answer:50(b)
Step-by-step explanation:
I just took the test
1.44 is more than 1.438 so the second brother