Given the function h(x)=x^2+14x+41, to solve by completing square we procced as follows;
x^2+14x+41=0
x^2+14x=-41
but;
c=(b/2)^2
and b=14
hence;
c=(14/2)^2=49
substituting the value of c in the expression we get:
x^2+14x+49=-41+49
x^2+14x+49=8
(x+7)^2=8
this can be written in vertex form;
h(x)=a(x-h)^2+k
where:
(h,k) is the vertex;
thus
(x+7)^2=8
h(x)=(x+7)^2-8
hence the vertex will be at the point:
(-7,-8)
<h2>
1080°</h2><h2>
</h2>
basically, the sum of all of the internal angles will be 1080
when you add all interior angles in an octagon you should get 1080
hope that helps !
Answer:
what's the question.. I'll help
Answer:
-2
Step-by-step explanation:
If x=0
-3(0)+2y=-4
-0+2y=-4
We can say
2y-0=-4
2y=-4
Dividing both side by 2,
y=-2
3x + 34
x = 4
Substitute x:
3 times 4 = 12
12 + 34 = 46
The answer is 46.
Hope this helped