All categories

2 years ago

How do I solve this question?

Mathematics

1 answer:

Jet001 [13]2 years ago

3 0

Answer:

n=2.5

Step-by-step explanation:

First, write an equation!

n+5n-6+2n+1=15

Now, combine like terms to make things easier.

8n-5=15

Cancel -5 from the left to isolate 5n as a variable.

8n-5+5=15+5

8n=20

Now divide both sides by 8.

8n/8=20/8

n=2.5

You might be interested in

A physical education class lasts for 7/8 -hour. How many minutes do they spend 1/2 of their playing time?

olchik [2.2K]

(7/8) of an hour is 52.5 minutes. If you are looking for half of that, it would be 26.25 minutes or 26 minutes and 15 seconds.

4 0

2 years ago

Three fourths of a number p less subtracted by 2 is 5 sixths of a number r plus 5

goldenfox [79]

Three fourths of a number p less subtracted by 2 is 5 sixths of a number r plus 5

3/4 of p subtracted by 2 is 5/6 of a r plus 5

3/4 of p - 2 is 5/6 of r + 5

$\frac{3}{4} p-2= \frac{5}{6} r+5$ <--- answer?

$\frac{3}{4} p= \frac{5}{6} r+7$

$\frac{3p}{4} = \frac{5r}{6} +7$

$\frac{3p}{4}* \frac{6}{5r} = 7$

$\frac{18p}{20r} = 7$

$\frac{9p}{10r} = 7$

$\frac{p}{r} = 7* \frac{10}{9}$

$\frac{p}{r} = \frac{70}{9}$ <-- answer?

Hope this helps

5 0

2 years ago

Find the slope of the line containing the points ( a , 1/a ) a n d ( b , 1/b )

xz_007 [3.2K]

Answer:

slope=(y2-y1)/(x2-x1)

=(1/b-1/a)/(b-a)

=((a-b)/ab)/(b-a)

=(a-b)/ab(b-a)

=(a-b)/(-(ab(a-b))

=-1/ab

5 0

2 years ago

The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and

Scorpion4ik [409]

Answer:

$\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)$

Step-by-step explanation:

The PDF of X is

$\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)$

The PDF of Y is

$\bf g(x)=\mu e^{-\mu x}\;(x\geq0)$

The means of X and Y are respectively,

$\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}$

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

$\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)$

7 0

2 years ago

Pls help me ASAP this is due today I’ll brainlest

dmitriy555 [2]

Answer:

Step-by-step explanation:

8 0

2 years ago