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Aleksandr [31]
3 years ago
15

How do I solve this question?

Mathematics
1 answer:
Jet001 [13]3 years ago
3 0

Answer:

n=2.5

Step-by-step explanation:

First, write an equation!

n+5n-6+2n+1=15

Now, combine like terms to make things easier.

8n-5=15

Cancel -5 from the left to isolate 5n as a variable.

8n-5+5=15+5

8n=20

Now divide both sides by 8.

8n/8=20/8

n=2.5

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Solving exponential equations with a common base problem in the picture!
Genrish500 [490]

<u>Given</u>:

The given expression is 18^{x^{2}+4 x+4}=18^{9 x+18}

We need to determine the solution of the given expression.

<u>Solution</u>:

Let us solve the exponential equations with common base.

Applying the rule, if a^{f(x)}=a^{g(x)} then f(x)=g(x)

Thus, we have;

x^{2}+4 x+4=9 x+18

Subtracting both sides of the equation by 9x, we get;

x^{2}-5 x+4=18

Subtracting both sides of the equation by 18, we have;

x^{2}-5 x-14=0

Factoring the equation, we get;

x^2-7x+2x-14=0

Grouping the terms, we have;

(x^2-7x)+(2x-14)=0

Taking out the common term from both the groups, we get;

x(x-7)+2(x-7)=0

Factoring out the common term (x - 7), we get;

(x+2)(x-7)=0

x+2=0 \ and \ x-7=0

   x=-2 \ and \ x=7

Thus, the solution of the exponential equations is x = -2 and x = 7.

Hence, Option C is the correct answer.

7 0
3 years ago
Chelsea takes the bus to school, but she walks home. The bus travels to the school at an average speed of 45 miles per hour. Whi
Neko [114]

Answer:

time walking=1-t hrs

ditace is same

therefore 2.5*(1-t)=45*t

2.5-2.5t=45t

t=2.5/46.5 hrs

this has only one solution since it is in linear form

4 0
3 years ago
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What mixed number is equal to 17/6
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Answer:2 5/6

Step-by-step explanation:

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4 years ago
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A researcher weighed cantaloupes grown across a certain
Luda [366]

Answer:B At least 4 pounds but less than 6 pounds.

Step-by-step explanation:

7 0
2 years ago
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34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
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