Question

Stuck, anyone can help?

Answer 1

Answer:

Step-by-step explanation:

$\sqrt{x-3}$ = x - 5 ( x ≥ 3 )

( $\sqrt{x-3}$ )² = ( x - 5 )²

x - 3 = x² - 10x + 25

x² - 11x + 28 = 0

(x - 4)(x - 7) = 0

$x_{1}$ = 7

$x_{2}$ = 4

Check the answer:

1). x = 7

$\sqrt{7-3}$ = 7 - 2

√4 = 2

2 = 2

2). x = 4

$\sqrt{4-3}$ = 4 - 5

1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.