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Semenov [28]
3 years ago
12

MATH HELP ASAP TYSM IF YOU PUT A RANDOM ANSWER YOU WILL BE REPORTED JUST GIVE ME THE ASNWER DON"T SHOW YOUR WORK TYSM

Mathematics
1 answer:
avanturin [10]3 years ago
3 0

Answer:

1,080

Step-by-step explanation:

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The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?
AleksAgata [21]

Answer:

\large \boxed{2}

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}

Check:

\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}

It checks.

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Step-by-step explanation:

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