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2 years ago

A store purchased model railroad sets for 400 and sold them for 444 what percentage is the mark-up

Mathematics

1 answer:

andrew-mc [135]2 years ago

4 0

Answer:

9.91%

Step-by-step explanation:

cost price= 400

selling price=444

profit made= 444-400

= 44

profit percentage= 44/444 ×100

=9.91%

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What is the area of the triangle?

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2 years ago

Select the simplification that accurately explains the following statement.

lutik1710 [3]

Answer:

Option (b) is correct.

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}=2^{1}=2$

Step-by-step explanation:

Given: $(2^\frac{1}{4} )^4$

We have too choose the correct simplification for the given statement.

Consider $(2^\frac{1}{4} )^4$

Using property of exponents, $(a^m)^n=a^m\times a^m\times a^m\times ....\times (n\ times)$

We have,

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}$

Again applying property of exponents $a^m\times a^m=a^{n+m}$

We have,

$(2^\frac{1}{4} )^4=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}$

Simplify, we have,

$(2^\frac{1}{4} )^4=2^{\frac{4}{4}}$

we get,

$(2^\frac{1}{4} )^4=2^{1}=2$

Thus, $(2^\frac{1}{4} )^4=2$

Option (b) is correct.

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2 years ago

A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery servic

sineoko [7]

Answer:

55.32% probability that a late package was delivered by express delivery service 2

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Late delivery.

Event B: Service 2 was used.

A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2.

100 - 35 = 65%.

So $P(B) = 0.65$

Service 2 has a record of 2.0% of packages being delivered late.

This means that $P(A|B) = 0.02$

Probability of a late delivery.

35% from service 1. Of those, 3% are late.

65% from service 2. Of those, 2% are late.

$P(A) = 0.35*0.03 + 0.65*0.02 = 0.0235$

What is the probability that a late package was delivered by express delivery service 2

$P(B|A) = \frac{0.65*0.02}{0.0235} = 0.5532$

55.32% probability that a late package was delivered by express delivery service 2

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2 years ago