What is the internal angle sum of a polygon with 21 sides?

Mathematics

2 answers:

sergij07 [2.7K]3 years ago

6 0

The interior angle of a regular 21-gon is around 162.86∘

Wittaler [7]3 years ago

3 0

162.86 is the answer to this!!

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Help thanksSSSSSSSSSS

Setler79 [48]

Answer:

$\boxed{\sf{x=24}}$

Step-by-step explanation:

<u>GIVEN:
</u>

To find the missing number in the proportion, you have to isolate it the term of x from one side of the equation.

$\sf{\dfrac{8}{7}=\dfrac{x}{21} }$

First, thing you do is switch sides.

$\sf{\dfrac{x}{21}=\dfrac{8}{7} }$

Multiply by 21 from both sides.

$\Longrightarrow: \sf{\dfrac{21x}{21}=\dfrac{8*21}{7} }$

Solve.

Multiply the numbers from left to right.

Use the order of operations.

PEMDAS stands for:

Parentheses
Exponents
Multiply
Divide
Add
Subtract

$\Longrightarrow: \sf{\dfrac{8*21}{7}=\dfrac{168}{7}=24 }$

$\Longrightarrow: \boxed{\sf{x=24}}$

<u>Therefore, the final answer is x=24.</u>

I hope this helps. Let me know if you have any questions.

3 0

2 years ago

Write the equation of a line that is perpendicular to the given line and that passes through the given point. 2x + 4y = –6; (2,

Anna [14]

First we have to find the slope of the given line. We do that by puttiing the equation into slope-interept form. or solving it for y (same thing). 2x + 4y = -6. We move the 2x over by subtraction to get 4y = -2x - 6. Divide both sides by 4 to get the slope-intercept form we are seeking. $y=-\frac{1}{2}x-\frac{3}{2}$ . The slope that is perpendicular to that slope of -1/2 is the opposite reciprocal. Therefore, the perpendicular slope is a positive 2/1 or just 2. If this new line goes through the point (2, 5), it goes through the x value of 2 and the y value of 5. We will use those values along with the slope of 2 to solve for b in our slope-intercept equation. That looks like this: $5=2(2)+b$ and b = 1. That means our new equation, the one that is perpendicular to the given line, has an equation of y = 2x + 1.