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4 years ago

If x+3y=7 and x-3y=1 what's y

Mathematics

1 answer:

vazorg [7]4 years ago

6 0

Subtract one equation from the other to eliminate x :

(x + 3y) - (x - 3y) = 7 - 1

6y = 6

y = 1

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3 years ago

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Aye someone please help ?

monitta

Answer:

The required rectangular form of the given complex polar form :

z1 = -3√2 - 3√2i

Step-by-step explanation:

$z_1=6[\cos (\frac{5\pi}{4}) + i\sin(\frac{5\pi}{4})]...........(1)\\\\Now,\cos (\frac{5\pi}{4})=\cos(\pi+\frac{\pi}{4})\\\\=-\cos(\frac{\pi}{4})\\\\=-\frac{1}{\sqrt{2}}\\\\And,\sin (\frac{5\pi}{4})=\sin(\pi+\frac{\pi}{4})\\\\=-\sin(\frac{\pi}{4})\\\\=-\frac{1}{\sqrt{2}}$

On substituting the obtained values in equation (1)

$z_1=6[\frac{-1}{\sqrt{2}}-i\cdot \frac{1}{\sqrt{2}}]\\\\\implies z_1=-3\sqrt{2}- 3\sqrt{2}\cdot i$

Hence, the required rectangular form of the given complex polar form :

z1 = -3√2 - 3√2i

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4 years ago

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