8+x ≥ 12
-8 -8
x ≥ 4
(i tried taking the picture)
How am I so supposed to solve the question without the picture?
Answer:
(-4,4)
Step-by-step explanation:
-5x-10y=-20
10x+10y=0
divide both sides by 2
-5x-10y=-20
5x+5y=0
that makes
-5y=-20
divide both sides by -5
y=4
now substitute 4 for y
10x+10 x 4=0
multiply
10x+40=0
subtract
10x=-40
divide
x=-4
Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
Answer:
3
Step-by-step explanation:
5+3=8 and on a number line 5 and 8 and 3 numbers away
