Since Christian sets aside $60 per month for daily coffee, and McDonalds sells coffee for $ 1, and The Bean Sprout sells a cup of coffee for $3, to create an equation that represents the combinations of coffee options that allow Christian to stay in his budget and provide 2 combinations that use his entire budget, 1 combination that would be under budget, and 1 combination that would be over his budget, the following linear equation must be proposed:
M + BS = 60
2 combinations using the entire budget =
- 15 McDonalds + 15 The Bean Sprout = 15 + 45 = 60
- 30 McDonalds + 10 The Bean Sprout = 30 + 30 = 60
1 combination under budget =
- 15 McDonalds + 10 The Bean Sprout = 15 + 30 = 45
1 combination over budget =
- 30 McDonalds + 30 The Bean Sprout = 30 + 90 = 120
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Answer:
7
Step-by-step explanation:
(x,y)
The probability that he will be rejected to at least one of the colleges is 0.51.
Given probability that he will admit in A is 0.7, probability that he will not be admit in B is 0.5, probability that atleast one of his applications got rejected is 0.6.
We have to find the probability that he will be rejected to at least one of the colleges.
Probability that he will admit in A =0.7
Probability that he will not admit in A=1-0.7=0.3
Probability that he will not admit in B =0.5
Probability that he will admit in B=1-0.5=0.5
Probability that he will be rejected to at least one of the colleges=probability that he will admit in A* probability that he will not admit in B+ probability that he will admit in B* probability that he will not admit in A+ probability that he will not admit in A* probability that he will not admit in B
=0.7*0.5+0.5*0.3+0.5*0.3
=0.35+0.15+0.15
=0.51
Hence the probability that he will be rejected to at least one of the colleges is 0.51.
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Step-by-step explanation:
7x - 15 =55
7x= 55 +15
7x =70
X=70/7
X=10
Hope this helps..
