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3 years ago

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Ms. Brown predicted that 25% of the days in January would have temperatures below 45°F. How many days does she predict will have

temperatures below 45°F?

1 answer:

Dmitriy789 [7]3 years ago

8 0

The answer is 7.75. Since there can not be 7.75 days, you can round that to 8 and say that it's almost 8 days. Hope this helps!

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I need help pleaseee!!!!!!!!!!

vovikov84 [41]

<h2>Answer:</h2>

Using the distributive property, we can simplify the expression.

4 × 3 = 12

4 × $\frac{1}{4}$ = 1

4 × $(-\frac{1}{2})$ = -2

Here is the simplified expression:

$12 + c - 2d$

6 0

3 years ago

Two trains going in opposite directions leave at the same time. Train B travels 30 mph faster than train A. In 5 hours the train

Angelina_Jolie [31]

Answer:

a

Step-by-step explanation:because

3 0

3 years ago

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

Give triangle ABC is a right triangle, and angle A is the right angle. If sin(B)=3/5, find the cos(B).

hichkok12 [17]

Answer:

Cos B = 4/5

Step-by-step explanation:

From the question given above, the following data were obtained:

Sine B = 3/5

Cos B =?

Recall:

Sine B = Opposite / Hypothenus

Sine B = 3/5

Therefore,

Opposite = 3

Hypothenus = 5

Next, we shall determine the Adjacent. This can be obtained as follow:

Opposite = 3

Hypothenus = 5

Adjacent =?

Hypo² = Adj² + Opp²

5² = Adj² + 3²

25 = Adj² + 9

Collect like terms

Adj² = 25 – 9

Adj² = 16

Take the square root of both side

Adj = √16

Adjacent = 4

Finally, we shall determine Cos B. This can be obtained as follow:

Hypothenus = 5

Adjacent = 4

Cos B =?

Cos B = Adjacent / Hypothenus

Cos B = 4/5

4 0

3 years ago

PLSSS help if you TURLY know:)

Ghella [55]

Answer:

7m+14 is the correct answer

6 0

3 years ago

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