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andreyandreev [35.5K]

3 years ago

9

Jordan weighed two buckets of sand for a geology project. The first bucket weighed 26.31 pounds. The other bucket weighed 4.39 p

ounds. How much do the two buckets of sand weigh all together?

2 answers:

san4es73 [151]3 years ago

6 0

Answer:

30.7

Step-by-step explanation:

frozen [14]3 years ago

6 0

Tje answer is 26,31+4,39=30,7

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Convert 22/3 into a mixed number

trasher [3.6K]

22/3= 7 1/3 hope that helped

6 0

3 years ago

Joelle bought some fruit at the store. They bought 5 apples and a bunch of bananas. The bananas cost $1.50, and the total cost w

Softa [21]

Answer:

$3.74

Step-by-step explanation:

we already know the cost of the banana's and it gives us the total price including apples. So $5.24 - $1.50 = $3.74, and the 3.74 is the cost of apples

4 0

3 years ago

9x - 3y = -42 and -9x + 8y =22

ASHA 777 [7]

Answer:

(-5 1/9, -4)

Step-by-step explanation:

Add the equations

5y=-20

y=-4

-9x+8(-4)=22

-9x-32=22

-9x=46

x= - 5 1/9

8 0

3 years ago

What is the standard equation of the circle in the diagram? ^

den301095 [7]

Answer:

$(x - 3)^{2} + (y + 4)^{2} = 4$

Step-by-step explanation:

Center is at (3, -4) and the radius is 2

$(x - 3)^{2} + (y + 4)^{2} = 4$

5 0

3 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

So

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

4 years ago