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OverLord2011 [107]
3 years ago
15

The statement of cash flows is an optional financial statement. True Or False

Mathematics
1 answer:
Helga [31]3 years ago
8 0

Answer:

The statement of cash flows is an optional financial statement. The statement of cash flows shows the effects on cash of a company's operating, investing, and financing activities. The statement of cash flows reports a firm's major sources of cash receipts and major uses of cash payments for a period.

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What are the solutions of the equation 9x4-2x2-7=0? Use u substitution to solve.<br>​
koban [17]

Answer:X=i and ±\sqrt{\frac{7}{9} }

Step-by-step explanation:

7 0
4 years ago
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Given |u| = 10 at ∠135° and |v| = 5 at ∠30°, what expression can be used to find |u + v|?
astraxan [27]

Answer:

B, 10^{2} + 5^{2}- 2(10)(5)cos(75)

Step-by-step explanation:

Using the law of cosines, which is c^{2}=a^{2}+b^{2}-2ab cos(C), you can simply insert all the values.

c=|u+v|

a= r value of u (10)

b= r value of v (5)

To find  C, you simply have to subtract v from u, and then subtract that number from 180 to find the reference angle.

I.E.: ∠135 - ∠30 = ∠105 ↔ 180 - 105 = 75 =  C

so, the completed equation would be 10^{2} + 5^{2}- 2(10)(5)cos(75)

5 0
3 years ago
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(HELP ASAP 16 MIN)<br><br> Find each function value.
Maru [420]

Answer:

(f o g) (x) = f(g(x)) = f(1) = 2 = 2

(g o f) (x) = g(f(x)) = g (2) = 1 = 1

Step-by-step explanation:

hope that helps!

5 0
3 years ago
Which of these is a function?
Usimov [2.4K]
{(0, 4), (2, 4), (3, 7), (4, 9)} is a function.
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4 years ago
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

t=2\cdot9.375=18.75

Hence, the rocket hits the ground after 18.75 seconds.

6 0
1 year ago
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