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emmasim [6.3K]
2 years ago
13

Math on the Spot Funtime Carnival charges a $3.00 entrance fee and $1.00 per

Mathematics
1 answer:
ahrayia [7]2 years ago
7 0
Create an equation for both carnivals and set them equal to each other 3+(1*e)=5+(.5*e)
The total amount of rides to be equal is 4 and the cost is $7
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Oscar is buying 4 new tires for his car. He has $240 budgeted for the tires, but can afford to pay $35 more or less than that am
Pachacha [2.7K]

Given that the dealer sells a dozen tires for $240, every 3-tire set costs $60. There are six 2-tire sets in a dozen. Thus, his total revenue should be $360. The total profit is the difference between the total revenue and the total cost. The answer is therefore, the first choice, $120.

4 0
3 years ago
Read 2 more answers
Julian study a dog walking business over his summer break. He charges $10 for every 1/3 hour he walks a dog if he increases his
Genrish500 [490]

Answer:

The amount of increase per \frac{1}{3}  hour by $1.

Step-by-step explanation:

Julian charges $10 for every \frac{1}{3} hour he walks a dog.

He increases his fee by 10%

Now we have to find 10% of $10

Amount increased = \frac{10}{100} .10 = 1

So the amount increased by $1.

The amount of increase per \frac{1}{3}  hour by $1.

6 0
2 years ago
In ΔEFG, e = 4.7 inches, f = 4.8 inches and g=3.6 inches. Find the measure of ∠E to the nearest 10th of a degree.
AleksAgata [21]

Answer:

66.3

Step-by-step explanation:

i just did it on deltamath

7 0
3 years ago
Solve For The Variable
sveta [45]

Answer:

V=25

Step-by-step explanation:

Solve for

v

v

by simplifying both sides of the equation, then isolating the variable.

v

=

25

6 0
2 years ago
Read 2 more answers
Try this please, it's about arcs and angles and I'm just not sure how to do it. Thanks!
Nataly_w [17]
Check the picture below.

the segment LOJ is a diameter, and therefore the arcLCJ made by that diameter will have a central angle of 180°.

that simply means that the arcLC is 180 - 94, or 86°.

the ∡LJC is an inscribed angle that is intercepting the arcLC, and therefore, by the inscribed angle theorem, it'll be half of arcLC.

3 0
3 years ago
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