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Sveta_85 [38]
3 years ago
5

The circumference of a circle is 87 cm. What is the DIAMETER of the circle?

Mathematics
2 answers:
harkovskaia [24]3 years ago
4 0

Answer:8 cm

Step-by-step explanation:

Basile [38]3 years ago
4 0
I think the answer is 8cm
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Find the equation of the line through point (1,−5) and perpendicular to y=1/8x+2. Use a forward slash (i.e. "/") for fractions (
Masteriza [31]

Answer:

y = -8x + 3

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept.

Perpendicular lines:

When two lines are perpendicular, the multiplication of their slopes is -1.

Perpendicular to y=1/8x+2

This line has slope \frac{1}{8}

So, for the line we want to find the equation, we have that:

\frac{m}{8} = -1

m = -8

So

y = -8x + b

Find the equation of the line through point (1,−5)

This means that when x = 1, y = -5. We use this to find b. So:

y = -8x + b

-5 = -8 + b

b = 3

The equation of the line is:

y = -8x + 3

7 0
3 years ago
What is an equivalent ratio to 8:20 and<br> 2:5?
coldgirl [10]

Answer:

4:10.

Step-by-step explanation:

4:10 would be one.

5 0
3 years ago
How do you change 7/10 to a percent​
Dimas [21]

Answer:70%

Step-by-step explanation: Convert the fraction to a decimal, then multiple by 100.

4 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
A trapezoid with a height of 8 feet and one base measuring 11 feet has an area of 112 ft.² find the length of the other base
sineoko [7]

Answer:

17

Step-by-step explanation:

The equation of a trapezoid is (a + b)/2 * h. So let's reverse the equation and divide the area by the height, 112/8 = 14. Now we should multiply it by 2, so we can get what a + b equaled. 28 = 11 + b

b = 17

4 0
3 years ago
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