Expand the brackets by multiplying everything in the brackets by -0.25.
-x x -0.25 = 0.25x
-12 x -0.25 = 3
0.25x + 3 = 2
-3 from both sides.
0.25x = -1
Divide both by 0.25
x = -4
Answer:
I am not sure about this question sry but u can try asking a tutor
Let's use Gaussian elimination. Consider the augmented matrix,
![\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\-1 & 2 & 3 & 0 & 1 & 0\\1 & 1 & 4 & 0 & 0 & 1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cccc%7D1%20%26%20-1%20%26%20-1%20%26%201%20%26%200%20%26%200%5C%5C-1%20%26%202%20%26%203%20%26%200%20%26%201%20%26%200%5C%5C1%20%26%201%20%26%204%20%26%200%20%26%200%20%26%201%5Cend%7Barray%7D%5Cright%5D)
• Add row 1 to row 2, and add -1 (row 1) to row 3:
![\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 2 & 5 & -1 & 0 & 1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cccc%7D1%20%26%20-1%20%26%20-1%20%26%201%20%26%200%20%26%200%5C%5C0%20%26%201%20%26%202%20%26%201%20%26%201%20%26%200%5C%5C0%20%26%202%20%26%205%20%26%20-1%20%26%200%20%26%201%5Cend%7Barray%7D%5Cright%5D)
• Add -2 (row 2) to row 3:
![\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cccc%7D1%20%26%20-1%20%26%20-1%20%26%201%20%26%200%20%26%200%5C%5C0%20%26%201%20%26%202%20%26%201%20%26%201%20%26%200%5C%5C0%20%26%200%20%26%201%20%26%20-3%20%26%20-2%20%26%201%5Cend%7Barray%7D%5Cright%5D)
• Add -2 (row 3) to row 2:
![\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cccc%7D1%20%26%20-1%20%26%20-1%20%26%201%20%26%200%20%26%200%5C%5C0%20%26%201%20%26%200%20%26%207%20%26%205%20%26%20-2%5C%5C0%20%26%200%20%26%201%20%26%20-3%20%26%20-2%20%26%201%5Cend%7Barray%7D%5Cright%5D)
• Add row 2 and row 3 to row 1:
![\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 5 & 3 & -1\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cccc%7D1%20%26%200%20%26%200%20%26%205%20%26%203%20%26%20-1%5C%5C0%20%26%201%20%26%200%20%26%207%20%26%205%20%26%20-2%5C%5C0%20%26%200%20%26%201%20%26%20-3%20%26%20-2%20%26%201%5Cend%7Barray%7D%5Cright%5D)
So the inverse is

Both of the digits in the hundreds and tens place are 4, making it a relationship. The 4 in the hundreds place is worth 400, the 4 in the tens place is worth 40, and the 0 in the ones place is worth 0.
Hope this helped!
Nate