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3 years ago

5

Which of the following shows √-25 simplified and written as a complex number?

1 answer:

geniusboy [140]3 years ago

3 0

Answer:

Math error

Step-by-step explanation:

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What is the radius of a circle with circumference 56 inches

pochemuha

Answer:

The answer is 8.91 or 8.9

Step-by-step explanation:

SInce the circumference is 56, you'll divide it by pi or 3.14. It's as if you're doing it backwards, but not always. After you divide it by 3.14, you'll get your diameter, or in this case, 17.8. Divide the diameter by 2 because the diameter is twice the radius. Eventually your final answer will be 8.91 or 8.9

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2 years ago

What is 3 2/3-1/9? What is the answer?

musickatia [10]

Answer:

3 5/9 or 32/9

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Zachary purchased a new car for $29,995. The value of the car linearly depreciated to $9,300 over 10 years. Write a linear equat

Sindrei [870]

Answer:

Step-by-step explanation:

y=-1,869.5x+27,995

Step-by-step explanation:

Let

x-----> the time in years

y----> value of Zachary’s car in dollars

A(0,27,995), B(10,9,300)

step 1

Calculate the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute

m=\frac{9,300-27,995}{10-0}=-1,869.50

step 2

Find the equation of the line

The equation of the line into slope intercept form is equal to

y=mx+b

we have

m=-1,869.50

b=27,995 -----> the y-intercept is the point A

substitute

y=-1,869.5x+27,995

hope this helps have a good day

6 0

3 years ago

Joshua drinks 8 cups of water a day The recoummended daily amount is given n fluid ounces How many fluid ounces water does he dr

Naily [24]

Joshua drinks 64 ounces each day because there are 8 ounces in 1 cup so 8ounces(8 cups)= 64 ounces

8 0

3 years ago

In a regression analysis involving 30 observations, the following estimated regressionequation was obtained.y^ =17.6+3.8x 1 −2.3

USPshnik [31]

Answer:

(a) There is a significant relationship between y and $x_1, x_2, x_3, x_4$

(b) $SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45$

(c) $SSE_{(x_2,x_3)} = 100$

(d) $x_1$ and $x_4$ are significant

Step-by-step explanation:

Given

$y = 17.6+3.8x_1 - 2.3x_2 +7.6x_3 +2.7x_4$ --- estimated regression equation

$n = 30$

$p = 4$ --- independent variables i.e. x1 to x4

$SSR = 1760$

$SST = 1805$

$\alpha = 0.05$

Solving (a): Test of significance

We have:

$H_o :$ There is no significant relationship between y and $x_1, x_2, x_3, x_4$

$H_a :$ There is a significant relationship between y and $x_1, x_2, x_3, x_4$

First, we calculate the t-score using:

$t = \frac{SSR}{p} \div \frac{SST - SSR}{n - p - 1}$

$t = \frac{1760}{4} \div \frac{1805- 1760}{30 - 4 - 1}$

$t = 440 \div \frac{45}{25}$

$t = 440 \div 1.8$

$t = 244.44$

Next, we calculate the p value from the t score

Where:

$df = n - p - 1$

$df = 30 -4 - 1=25$

The p value when $t = 244.44$ and $df = 25$ is:

$p =0$

So:

$p < \alpha$ i.e. $0 < 0.05$

Solving (b): $SSE(x_1 ,x_2 ,x_3 ,x_4)$

To calculate SSE, we use:

$SSE = SST - SSR$

Given that:

$SSR = 1760$ ----------- $(x_1 ,x_2 ,x_3 ,x_4)$

$SST = 1805$

So:

$SSE_{(x_1 ,x_2 ,x_3 ,x_4)} = 1805 - 1760$

$SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45$

Solving (c): $SSE(x_2 ,x_3)$

To calculate SSE, we use:

$SSE = SST - SSR$

Given that:

$SSR = 1705$ ----------- $(x_2 ,x_3)$

$SST = 1805$

So:

$SSE_{(x_2,x_3)} = 1805 - 1705$

$SSE_{(x_2,x_3)} = 100$

Solving (d): F test of significance

The null and alternate hypothesis are:

We have:

$H_o :$ $x_1$ and $x_4$ are not significant

$H_a :$ $x_1$ and $x_4$ are significant

For this model:

$y =11.1 -3.6x_2+8.1x_3$

$SSE_{(x_2,x_3)} = 100$

$SST = 1805$

$SSR_{(x_2 ,x_3)} = 1705$

$SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45$

$p_{(x_2,x_3)} = 2$

$\alpha = 0.05$

Calculate the t-score

$t = \frac{SSE_{(x_2,x_3)}-SSE_{(x_1,x_2,x_3,x_4)}}{p_{(x_2,x_3)}} \div \frac{SSE_{(x_1,x_2,x_3,x_4)}}{n - p - 1}$

$t = \frac{100-45}{2} \div \frac{45}{30 - 4 - 1}$

$t = \frac{55}{2} \div \frac{45}{25}$

$t = 27.5 \div 1.8$

$t = 15.28$

Next, we calculate the p value from the t score

Where:

$df = n - p - 1$

$df = 30 -4 - 1=25$

The p value when $t = 15.28$ and $df = 25$ is:

$p =0$

So:

$p < \alpha$ i.e. $0 < 0.05$

<em>Hence, we reject the null hypothesis</em>

7 0

3 years ago