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Bogdan [553]
3 years ago
10

How do you solve -178=-5x+4(-4x-13)

Mathematics
1 answer:
Effectus [21]3 years ago
5 0

Answer:

x = 6

Step-by-step explanation:

  • <em><u>Pull out like factors: </u></em>

-4x - 13  =   -1 • (4x + 13)

  • <em><u>Equation at the end of step 2: </u></em>

 -178 -  (-5x +  -4 • [4x + 13] )  = 0

  • <em><u>Pull out like factors: </u></em>

  21x - 126  =   21 • (x - 6)

  • <em><u>Equation at the end of step 4: </u></em>

 21 • (x - 6)  = 0

  • <em><u>Solve:</u></em>

x-6 = 0  

  • <em><u>Add 6 to both sides of the equation:</u></em>

x = 6

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Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r
ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = \frac{\sum X}{n} = 21.88 ounces

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.201 ounces

            n = sample of boxes = 12

            \mu = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.796 < t_1_1 < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.796) = 0.90

P( -1.796 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.796 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.796 \times {\frac{s}{\sqrt{n} } } , \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 21.88-1.796 \times {\frac{0.201}{\sqrt{12} } } , 21.88+1.796 \times {\frac{0.201}{\sqrt{12} } } ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

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blondinia [14]

Answer:

b = 40 and -40

Step-by-step explanation:

General form of Perfect square trinomial is a 2 + 2 a b + b 2

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The perfect square is ( 4 x − 5 ) 2 = 16 x 2 − 40 x + 25 .

if we consider a=4x and b=5 (same sign), then − b x = 2 ( 4 x ) ( 5 ) − b x = 40 x b = − 40

The perfect square is ( 4 x + 5 ) 2 = 16 x 2 + 40 x + 25 .

The first solution ( 4 x − 5 ) 2 is the best solution after comparing the expression given.  I hope this helps, xx .

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Answer:

60 cm^2 (dark blue)

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Since a rhombus's diagonal bisect each other, the diagonal's full length is 10 and 12. From there the area is 10*12 / 2 which is 60

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Otrada [13]

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A

Step-by-step explanation:

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