The diagonals of a quadrilateral are congruent and perpendicular bisectors of each other. what must the parallelogram be

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

Mr. Wilson drives 450 miles in seven hours. At this rate, about how many miles does he drive in six hours? A) 101 B) 254 C) 340

Deffense [45]

I think D is the answer hope this helps

5 0

2 years ago

2n-3/5=5 solve for n

dezoksy [38]

N=14/5 thats the answer.

3 0

3 years ago

Read 2 more answers

what is 372x19+89 WANT FREE POINTS? COME HERE SHHHH! I HAVE TO ASK A QUESTION SO IT DOESNT GET DELETED! LET ME KNOW IF YOU WANT

soldi70 [24.7K]

Answer:

7157

Step-by-step explanation:

Answer is 7157

3 0

3 years ago

Read 2 more answers

The number of Atlantic blue fin tuna in thousands can be modeled by P(x)=230(.881)^x where X represents the number of years sinc

Maurinko [17]

<h3>Answer: 1981</h3>

===================================

Work Shown:

Recall that P is in thousands, so P = 95 means 95,000.

Plug in P(x) = 95. Solve for x. Use logarithms to get this done.

P(x)=230(0.881)^x

95=230(0.881)^x

95/230 = (0.881)^x

0.41304347826087 = (0.881)^x

(0.881)^x = 0.41304347826087

Log( (0.881)^x )= Log( 0.41304347826087 )

x*Log( 0.881 )= Log( 0.41304347826087 )

x= Log( 0.41304347826087 )/Log( 0.881 )

x= 6.97883817154785

x= 7

Approximately 7 years after 1974 is when the population will be around 95,000.

7 years after 1974 = 1974+7 = 1981

8 0

2 years ago