Where R is the median between Q and L:
From my understanding of a triangle's centroid, it divides an angle bisector into parts of 2/3 and 1/3. In the given problem, these divisions are NS and SR. Therefore, twice SR would be equal to NS. From here, we can get the value of X, to solve for SR.
NS = 2SR
(x + 10) = 2(x + 3)
x + 10 = 2x + 6
x = 4
Therefore, SR = (x + 3) = 7
Answer:
Using c++
Check the image for colors.
Step-by-step explanation:
#include <iostream>
using namespace std;
int main()
{
float length1,length2,width1,width2,area1,area2;
cout<<"length of Rectangle 1\n";
cin>>length1;
cout<<"\nwidth of Rectangle 1\n";
cin>>width1;
cout<<"\nlenght of Rectangle 2\n";
cin>>length2;
cout<<"\nwidth of Rectangle 2\n";
cin>>width2;
area1=length1*width1;
area2=length2*width2;
if (area1<area2)
{cout << "\nRectangle 2 has greater area";}
else {
if (area1>area2)
{cout << "\nRectangle 1 has greater area";}
else {cout << "\nAreas are the same";}
}
return 0;
}
15/60 is the Awnser. Cuz 3•5 is 15 and 10•6 is 60
0.9x12=10.8,, 10.8-6.3=4.5. The number is 12
as we know that <span>If the 4" side of the card was scaled up to 10.5
then the scaling factor is 10.5/4 = 2.625.
The 5 side would be the length 5 x 2.625 = 13.125 which exceeds the maximum dimension of 11.
Thus, it is the 5 side which is scaled up to 10.5 and the scaling factor is therefore 10.5/5 = 2.1.
The scaled up length of the 4 side is thus 4 x 2.1 = 8.4.</span>
