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3 years ago

How many meters are equivalent to x centimeters????

Mathematics

1 answer:

katrin2010 [14]3 years ago

4 0

Answer:

1 Meter is equal to 100 centimeters.

Step-by-step explanation:

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3. What unit would you use to measure the weight of a school bus? *

larisa [96]

Answer:

Tons

Step-by-step explanation:

A school bus should be weighed in tons due to the fact that it definitely weighs more than a few pounds.

4 0

3 years ago

PLEASE HELP MEEE!

evablogger [386]

Hope this helps.
The answer is 4a-3b

7 0

3 years ago

2. A university admitted 100 students who transferred from other institutions. Of these students, 34 transferred from two-year c

antoniya [11.8K]

Answer:

So probability will be 0.34

Step-by-step explanation:

We have given that a university admitted 100 students

In which 34 students are from two year community program

25 students are from private four year institution

And rest that is 100-34-25 = 41 students from public four year institutions

Number of ways for selecting two students from two year community program that is, from 34 students

$=^{34}C_2$

And the number of ways in selecting the 2 students from total student $=^{100}C_2$

So probability will be $P=\frac{^{34}C_2}{^{100}C_2}=\frac{17}{50}=0.34$

8 0

4 years ago

What is the measurement of PQ?

Sholpan [36]

<em>The measure of PQ is 12.72</em>

<h2>Explanation:</h2>

We have the right triangle ΔPQR and we want to know the measure of PQ. PQ is opposite to ∠R, so from trigonometry we know that:

$sin(\alpha)=\frac{Opposite \ side}{Hypotenuse} \\ \\ \\ Here: \\ \\ \alpha=m\angle R=58^{\circ} \\ \\ Opposite \ side=\overline{PQ} \\ \\ Hypotenuse=\overline{RQ}=15 \\ \\ \\ So: \\ \\ sin(58^{\circ})=\frac{\overline{PQ}}{15} \\ \\ \\ Isolating \ \overline{PQ}: \\ \\ \overline{PQ}=15sin(58^{\circ}) \\ \\ \overline{PQ}=15(0.848)\\ \\ \boxed{\overline{PQ}=12.72}$

<h2>Learn more:</h2>

Right triangles: brainly.com/question/10252821

#LearnWithBrainly

7 0

4 years ago

Towers A and B are located 5 miles apart. A ranger spots a fire at a 42-degree angle from tower A. Another fire ranger spots the

lord [1]

Answer: The fire is 3.5 miles from tower B

Step-by-step explanation: Please refer to the attached diagram. The triangle in the attached diagram illustrates the clues given in the question. Both rangers are standing at points A and B respectively with a distance of 5 miles between them, which is line AB. Also, one ranger spots a fire from a tower at an angle of 42 degrees, which is point A. Another ranger spots the same fire from another tower, but from an angle of 64 degrees, which is point B. The fire is at point C on the triangle. Now we have a triangle with only one side known (5 miles) and three angles known (the third angle is computed as 180 - {64+42} which equals 74) which are 64 degrees, 42 degrees and 74 degrees.

The distance from the fire to tower B is calculated using the law of sines. (Note that this is not a right angled triangle, hence we cannot use trigonometric ratios). The law of sines is expressed as follows;

a/SinA = b/SinB or

a/SinA = c/SinC

Depending on the sides and angles we are given and the ones we are to calculate.

The distance from the fire to tower B is line BC, labeled as a in our diagram. Using the law of sines

a/SinA = c/SinC

(Note also that a is directly facing angle A, c is directly facing angle C, and so on)

a/SinA = c/SinC

a/Sin 42 = 5/Sin 74

By cross multiplication we now have

a (Sin 74) = 5 (Sin 42)

Divide both sides of the equation by Sin 74 and we now arrive at

a = 5 (Sin 42)/Sin 74

a = 5 (0.6691)/0.9613

a = 3.3455/0.9613

a = 3.4802

{rounded to the nearest tenth of a mile, a equals 3.5}

Therefore the distance from tower B to the fire is approximately 3.5 miles

3 0

3 years ago