<h3>
Answer: 8.323 (approximate)</h3>
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Explanation:
s = 32 = sample standard deviation
n = 40 = sample size
Despite not knowing the population standard deviation (sigma), we can still use the Z distribution because n > 30. When n is this large, the student T distribution is approximately the same (more or less) compared to the standard Z distribution. The Z distribution is nicer to work with.
At 90% confidence, the z critical value is roughly z = 1.645. This can be found using either a Z table or a calculator.
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We have these values:
- z = 1.645 (approximate)
- s = 32
- n = 40
Plug these values into the margin of error formula.
The margin of error is roughly 8.323
I rounded to 3 decimal places because z = 1.645 is rounded to 3 decimal places. If your teacher wants some other level of precision, then be sure to follow those instructions.
There are 5 hotels. Each of these 3 people will have 5 ways to choose the hotel. By basic principle of counting, the total number of ways to which the hotels can be chosen is equal to ,
5 x 5 x 5
That is, multiplying the number of ways each can choose the hotel. The answer is 125.
If each of them are to stay in different hotels, the first one will have 5 choices. The second will have only 4. Lastly, the third will only have 3 choices. That is,
5 x 4 x 3 = 60
We divide the second answer by the total and multiply by 100% to get the probability.
P = (60/125) x 100%
P = 48%
<em>ANSWER: 48%</em>
Answer:
4 is the median to your problem