A school club is raising money for a trip, and needs to reach $10,000. Their fundraising progress is modeled by the function
1 answer:
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Answer:
a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.
Step-by-step explanation:
For a) b) and c) we will use the empirical rule, so, we can observe the image shown below
a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%
b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%
c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.
d) The z-score related to 208 is = (208-196.99)/7.12 = 1.5 and the z-score related to 185 is
= (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.
Answer:
Step-by-step explanation:
a) Estimate for population mean = Sum/n =
b) Variance = 0.099208
Std dev = 0.314974
Std error = 0.0950
For 95% margin of error = 1.96*Std error
=0.1861
Confidence interval =
Interpretation of confidence interval:
A) if repeated samoles are taken, 95% of them will have a sample pH of rain water between [ ] & [ ].
For 99% CI, z value = 2.59
Conf interval = (4.6790, 5.1710)
C)if repeated samoles are taken, 99% of them will have a sample pH of rain water between [ ] & [ ].
As the level of confidence increases l, the width of the interval[ increases] this makes sense since the [ margin of error] [increases]