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Inessa05 [86]
3 years ago
10

A sphere has a volume of approximately 24,416.64 cubic inches (using 3.14 for ).

Mathematics
1 answer:
Masteriza [31]3 years ago
4 0

Answer:

diameter = 36 in.

Step-by-step explanation:

V = 4π r^3/3

24416.64 = (4(3.14) r^3)/3

73249.92 = 12.56 r^3

r^3 = 5832

r = cube root of 5832 = 18

diameter = 36 in.

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marusya05 [52]

Answer:

(a) The sample space is: S = {bb, bg, gb, gg}

(b) The probability that the couple has two girl children is 0.25.

(c) The probability that the couple has exactly 1 boy and 1 girl child is 0.50.

Step-by-step explanation:

A boy child is denoted by, <em>b</em>.

A girl child is denoted by, <em>g</em>.

(a)

A couple has two children.

The sample space for the possible gender of the two children are:

The couple can have two boys, two girls or 1 boy and 1 girl.

So the sample space is:

S = {bb, bg, gb, gg}

(b)

It is provided that the outcomes of the sample space <em>S</em> are equally likely, i.e. each outcome has the same probability of success.

Compute the probability that the couple has two girl children as follows:

P (2 Girls) = Favorable no. of outcomes ÷ Total no. of outcomes

                =\frac{1}{4} \\=0.25

Thus, the probability that the couple has two girl children is 0.25.

(c)

Compute the probability that the couple has exactly 1 boy and 1 girl child as follows:

P (1 boy & 1 girl) = Favorable no. of outcomes ÷ Total no. of outcomes

                          =\frac{2}{4} \\=0.50

Thus, the probability that the couple has exactly 1 boy and 1 girl child is 0.50.

7 0
3 years ago
A function, f(x) = 4x + 5, has a domain 0 &lt; x &lt; 50. What is its range?
Roman55 [17]

Answer:

f(x) = 4x+5 ; 0 ≤ x ≤ 50

 

The range is the possible output values of f(x)

 

4(0) + 5 = 5       smallest output value in range

4(50) + 5 = 55    largest output value in range

 

The outputs are between 5 and 55 including the endpoints so

the range is [5, 55]

7 0
3 years ago
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andrey2020 [161]

Answer:

Step-by-step explanation:

This question is incomplete; here is the complete question.

A closed cylindrical can of fixed volume V has radius r. (a) Find the surface area, S, as a function of r. (b) What happens to the value of S approaches to infinity? (c) Sketch a graph of S against r, if  V=10 cm³.

A closed cylindrical can of volume V is having radius r and height h.

a). Surface area of a cylinder is given by

S = 2(Area of the circular sides) + Lateral area of the can

S = 2πr² + 2πrh

S = 2πr(r + h)

b). Since surface area is directly proportional to radius of the can

S ∝ r

Therefore, when r approaches to infinity (r → ∞)

c). If V = 10 cm³ Then we have to graph S against r.

From the formula V = πr²h

10 = πr²h

h = \frac{10}{\pi r^{2}}

By placing the value of h in the formula of surface area,

S = 2\pi r(r+\frac{10}{\pi r^{2}})

Now we can get the points to plot the graph,

r       -2             -1         0       1            2

S    -13.72     -13.72     0    26.28    35.13

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Answer:

B) 42 units squared

Step-by-step explanation:

12 * 7 = 84

84 / 2 = 42

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0.9625

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