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3 years ago

Rewrite the percentage in the sentence below as a decimal.

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

6 0

Answer:

0.072

Step-by-step explanation:

vladimir1956 [14]3 years ago

4 0

Answer:0.072

Step-by-step explanation:

7.2% = 7.2/100

7.2 ➗ 100=0.072

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Simplify this expression. Write your answer using positive exponents.<br>

storchak [24]

What expression ? There isn’t one

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2 years ago

HELP ME PLEASE!!!!!!!

romanna [79]

Answer:what’s your question

Step-by-step explanation:

4 0

3 years ago

Which value of a makes the equation 13=40-3a

weeeeeb [17]

The value of A is 9. This is because 40-13= 27
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3 0

3 years ago

-6+x/x^4 limit at x →0

Jlenok [28]

Answer:

not existing

Step-by-step explanation:

$\frac{ - 6 + x}{ {x}^{4} }$

lim x goes to 0 is

$\frac{ - 6 + 0}{ {0}^{4} } = \frac{ - 6}{0}$

so not exist

I'm not sure if u mean that or this

7 0

3 years ago

A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

3 years ago