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3 years ago

What is the slope of the line that passes through the points (2,0) and

Mathematics

2 answers:

Firlakuza [10]3 years ago

4 0

Answer:

-1/6

Step-by-step explanation:

Y_Kistochka [10]3 years ago

3 0

Answer:

slope = - $\frac{1}{6}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (2, 0) and (x₂, y₂ ) = (32, - 5)

m = $\frac{-5-0}{32-2}$ = $\frac{-5}{30}$ = - $\frac{1}{6}$

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3 years ago

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3 years ago

What is the congruence theorem used to prove that the two triangles are congruent?

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2 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ,0)(, plus minus, square root o

Alchen [17]

Answer:

The equation of ellipse centered at the origin

$\frac{x^2}{18} +\frac{y^2}{10} =1$

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are $c^2=a^2-b^2$

$a^{2} = c^{2} +b^{2}$

$a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}$

$a^{2} =18$

$a=\sqrt{18}$

The equation of ellipse formula

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

we know that $a=\sqrt{18} and b=\sqrt{10}$

Final answer:-

The equation of ellipse centered at the origin

$\frac{x^2}{18} +\frac{y^2}{10} =1$

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3 years ago

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An introduction to equations x-3=10

stich3 [128]

Answer:

x - 3 = 10

x = 13 is the solution

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3 years ago

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