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Archy [21]
3 years ago
9

Vern has just opened a flower shop. Because of the startup costs, for the next month his net earnings for each bouquet are −$2.5

0. On Tuesday during that month, he sold 20 bouquets. What are Vern's net earnings for Tuesday?
Mathematics
1 answer:
Basile [38]3 years ago
6 0

Answer:

-$200

Step-by-step explanation:

Given that:

Net earning per bouquet for the month= - $2.50

On a particular day of the month, 20 bouquet was sold ;

Net earning for the day:

Net earning per bouquet * number of bouquet

-$2.50 * 80

= $200

Hence, net earning for Tuesday = - $200

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How do you change 2/5 to a precent
nikklg [1K]

Answer:

40%

Step-by-step explanation:

Percent is how much out of 100.

We have 2/5, so find equivalent fractions:

2/5 = 4/10 = 40/100

2/5 = 40%

8 0
3 years ago
87 is 15% of what number​
jarptica [38.1K]

Answer:

580

Step-by-step explanation:

Let's translate this word for word.

87 is 15% of what number

87 = 15% times x

87=.15 times x

87=.15 \cdot x

Divide both sides by .15

\frac{87}{.15}=\frac{.15x}{.15}

Cancel out the common factor of .15 on the right; that is .15/.15=1.

580=x

580 is the number

8 0
3 years ago
Read 2 more answers
9. Given the point (6,-8) values of the six trig function.
lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10  

\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}

3 0
3 years ago
Combine the like terms to create an equivalent expression:<br> -3r- 6+ (-1)
Norma-Jean [14]

Answer:

-3r+5 is that answer hdj

7 0
3 years ago
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A principal of $1,000 is invested in an account paying an annual interest rate of 6%.
Evgesh-ka [11]

A(t) = P(1+(r/n))^(nt)

A(5) = 1000(1+0.12/2)^(2*5)

A(5) = 1000(1.06)^(10)

A(5) = $1790.85

6 0
3 years ago
Read 2 more answers
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