Iluguru sold an artick to bol to gain 20% Thereafteru

Mathematics

1 answer:

Anastasy [175]3 years ago

8 0

Answer: £5

Step-by-step explanation:

Bole sold the article for 125% while he bought it for 100%.

Bole sold for £7.50 so £7.50=125%

£7.50/1.25=£6

125%/1.25=100%

£6=100% (the cost Bole bought the article with from Iluguru)

Iluguru sold it at 120% so 120% is £6

To find 100% we divide by 1.2

£6/1.2=£5

Iluguru bought article for £5 originally

You might be interested in

Writing an Equa

kakasveta [241]

Answer:

Step-by-step explanation:

(3,1) lies below the vertex, so the parabola opens downwards.

Equation for a down-opening parabola with vertex (2,3):

y = a(x-2)² + 3, a<0

Plug in (3,1) and solve for a:

1 = a1² + 3

a = -2

y = -2(x-2)² + 3

6 0

2 years ago

The sum of two numbers is twice their difference. The larger number is 2 more than twice the smaller

Alexandra [31]

The larger number is 6 and the smaller one is 2.

7 0

3 years ago

9. Given the point (6,-8) values of the six trig function.

lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10

$\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}$

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

$\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}$