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VashaNatasha [74]
2 years ago
15

At a restaurant, bill and his four friends decided to divide the bill evenly. If each person paid $12, what was the total bill?

Mathematics
1 answer:
Darya [45]2 years ago
7 0

Answer:

total=$60

Step-by-step explanation:

Including bill there's a total of 5 people

take what each person paid, $12, and multiply by the number of people

$12(5)=$60

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dmitriy555 [2]

Answer:

C

Step-by-step explanation:

2|6+p|-3p³,

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2|6+p|-3p³=2|6-2|-3(-2)³

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3 years ago
What's 2×8=??????????????????????????
Fynjy0 [20]

The answer is 16

8+8 = 16 which is 2*8

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Have a nice day❤︎

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<em>Kearsi</em>

5 0
3 years ago
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forsale [732]

Answer:

7.8(tan 67)

Step-by-step explanation:

7.8(tan 67)

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3 years ago
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An object is moving at a speed of 6 miles per month. Express this speed in feet per hour
patriot [66]

Answer:

44 feet/hour

Step-by-step explanation:

6mi/month(5280ft/1mi)(1month/30days)(1day/24hrs)

Assuming the month has 30 days, object moves at 44 feet/hour. You want all the units to cancel till you get the ones you need, in this case feet/hr.

7 0
3 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
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