V1/T1 = V2/T2
V1 = 350. mL
T1 = 25 + 273 = 298 K
V2 = 250. mL
T2 = ?
Solve the equation for T2: T2 = V2T1/V1 = (250. mL)(298 K)/(350. mL) = 213 K = -60°C
Answer:
There are parts of the ocean where hardly any rain falls but warm dry winds cause lots of evaporation. This evaporation removes water – when water vapour rises into the atmosphere, it leaves the salt behind, so the salinity of the seawater increases. This causes the seawater to become denser.
Answer:
Amount of heat required = 2810.5 J
Explanation:
Given data:
Mass of copper = 29.2 g
Initial temperature = 25°C
Final temperature = 275°C
Amount of heat required = ?
Solution:
Specific heat capacity of copper is 0.385 j/g.°C.
Formula:
Q = m×c×ΔT
ΔT = 275°C - 25°C
ΔT = 250°C
Q = 29.2 g × 0.385 j/g.°C ×250°C
Q = 2810.5 J
