Answer:
It is not valid since there is more than one variable being changed at one.
Step-by-step explanation:
Jackson changed the brand of soil, but he also changes the amount of water, and the amount of sunlight the plants are receiving, so his conclusion that the soil was more effective is not valid.
The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.
In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:
Z = X-ц / σ
· It measures how many standard deviations the measure is from the mean.
· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ
σ = σ /
σ is standard deviation
n is the sample size.
Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.
⇒ ц = 176.1 and σ = 35.4
For a sample of 43 passengers, we have
n = 43
σ = 
σ = 5.398
Z = X-ц / σ
Z = 
Z = -2.05 has p- value of 0.9798
The probability that the aircraft is loaded is
1 - p-value of Z
1 - 0.0202 = 0.9798
The probability that the aircraft is overloaded is 97.98%
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Answer:
$2327.5
Step-by-step explanation:
The stock of company A lost 2% today .
Let the price of the stock at the beginning of the day be A.
Therefore, a 2% loss of A = $46.55
That’s
2% /100% x A = $46.55
0.02 x A = $46.55
Divide both sides by 0.02
0.02/0.02 x A = $46.55/0.02
A = $2327.5
The price of stock at the beginning of the opening day was $2327.5
Step-by-step explanation:
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Answer:
Answer
5.0/5
23
Let's find the unit rate stemming from $18 for 4 games:
$18
------------- = $4.50/game
4 games
Let's do the same for $27 for 6 games:
$27
------- = $4.50/game (same as before)
6 g
Thus, the const. of prop. is $4.50/game, and the cost function is
C(x) = ($4.50/game)x, where x is the # of games played.