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____ [38]
3 years ago
14

Need answers plz would be appreciated

Mathematics
1 answer:
Archy [21]3 years ago
5 0

Answer:

1) x=5

2) x=7

3) x=8

4) x=4

5) x=7

6) x=8

Step-by-step explanation:

Since each pair is similar, their sides are in ratio:

1)

(2x+2)/6=18/9

2x+2=2*6

2x=12-2

x=10/2

x=5

2)

(x-2)/4=10/8

x-2=1.25*4

x=5+2

x=7

3)

(3x-6)/12=24/16

3x-6=1.5*12

3x=18+6

x=24/3

x=8

4)

(2x+4)/15=16/20

2x+4=0.8*15

2x=12-4

x=8/2

x=4

5)

(x+2)/15=6/10

x+2=0.6*15

x=9-2

x=7

6)

(-3+x)/6=10/12

-3+x=6*(10/12)

x=5+3

x=8

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The simple interest on a certain sum for 5years at 8% per annum is Rs200 less than the simple interest on the same sum for 3year
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Answer:

Step-by-step explanation:

The simple interest on a certain sum for 5years at 8% per annum is Rs200 less than the simple interest on the same sum for 3years and 4months at 18% per annum.Find the sum​

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From above question, we have to find the Principal

The simple interest on a certain sum for 5years at 8% per annum is Rs200

Hence,

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The simple interest on the same sum for 3years and 4months at 18% per annum.

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Hence,

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7 0
3 years ago
In a chess club the probability that Shaun will beat Mike is 3/8 .
romanna [79]

Answer:

\frac{10}{56} = 0.1786 probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

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So 1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8} probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So 1 - \frac{5}{7} = \frac{2}{7} probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786

\frac{10}{56} = 0.1786 probability that Shaun loses both games

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