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2 years ago

9

swame and luigi were printing calendars swame used 21/2 cartridge, while luigi used 1 3/4 ink cartridges. how many more ink cart

ridges swame used than luigi?

1 answer:

nirvana33 [79]2 years ago

8 0

I’m not sure if this is correct but the answer would be 8.75 well that’s what I got hope this helps and if it dead pls give me a thanks

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iren [92.7K]

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Step-by-step explanation:

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2 years ago

Six copies of a book cost $90. How much does<br> each copy of the book cost?

IRINA_888 [86]

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1 year ago

Read 2 more answers

Round this number to the tens place 645.56

arlik [135]

Answer:

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Step-by-step explanation:

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2 years ago

Is (8, 2) a solution to this system of inequalities?<br><br> y ≥ x + 1<br> y ≤ 2

Nostrana [21]

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2 years ago

A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph

belka [17]

Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

P(Smoker) =

$P(S) = \dfrac{340}{2000}=0.17$

P(emphysema) =

$P(E) = \dfrac{25}{2000}= 0.0125$

P(Smoker and emphysema) =

$P(S\cap E) = \dfrac{21}{2000} = 0.0105$

Two events A and B are said to be independent if

$P(A\cap B)=P(A)\times P(B)$

Checking conditions for independence:

$P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)$

Thus, the events being a heavy smoker and having emphysema are not independent.

3 0

2 years ago