Answer:
an enzyme produced chiefly by certain bacteria, having the property of cleaving DNA molecules at or near a specific sequence of bases.
Answer:
If an inhibitory synapse fires at the same time and at the same distance from the initial segment as an excitatory synapse of the same intensity there will be no changes in the potential in the firing zone.
Explanation:
Under normal conditions, the transmembrane potential depends on the ionic charges present in the intracellular and extracellular spaces. The extracellular space load is usually positive and in the cytoplasm is negative.
- <u>Depolarization</u> occurs by opening ion channels that allow sodium to enter the cell, making the intracellular space more positive.
- An opening of potassium channels releases this ion to the extracellular space, leading to <u>hyperpolarization</u>.
An excitatory synapse is one capable of depolarizing a cell and boosting the production of action potential, provided it is capable of reaching the threshold of said potential.
On the other hand, an inhibitory synapse is able to hyperpolarize the cell membrane and prevent an action potential from originating, so that they can inhibit the action of an excitatory synapse.
The interaction between two synapses, one excitatory and one inhibitory, -called synapse summation- will depend on the strength that each of them possesses. In this case, the intensity of both synapses being the same, there will be no changes in the membrane potential in the firing zone.
Learn more:
Excitatory and inhibitory postsynaptic potentials brainly.com/question/3521553
Answer:
Cruciferous
Explanation:
Their consumption is linked with lower rates of cancer and is believed to be associated with their sulfur containing phytochemicals
The question is incomplete as it lacks the multiple options. The multiple option are as follows;
Careful monitoring for level of consciousness and resolution of hypoglycemia
.
IV infusion of 50% dextrose and water solution
.
Administration of subcutaneous glucagon
Administration of 15 to 20 g of glucose in a concentrated carbohydrate source
Answer:
Administration of 15 to 20 g of glucose in a concentrated carbohydrate source.
Explanation:
The insulin and glucagon hormone maintains the blood glucose level in the humans. In case of Type I diabetes a little amount or no amount of insulin is made by the pancreas.
The wife of a man has caused insulin error that creates hypoglycemic condition means the individual has low blood glucose level. The intake of carbohydrates can increase his blood glucose level. The wife should give 15 to 20 g of glucose to make the conditions normal.
Thus, the answer is option (4).
So you know what is what and where it goes
