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GuDViN [60]
3 years ago
5

The sum of three numbers is 110. The third number is 3 times the first. The second number is 5 more than the first. What are the

numbers?
Please help me I've been trying to figure it out for a while but I cant
Mathematics
1 answer:
g100num [7]3 years ago
6 0

Answer:

The numbers are 63, 26, & 21

Step-by-step explanation:

110 = 3x + (5 + x) + x

105 = 3x + 2x

105 = 5x

21 = x

Plug it back into the first equation to find your values

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Answer:

1.5

Step-by-step explanation:

To find the midpoint, add the two coordinates and divide by 2

( -4+7)/2 =

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1.5

The midpoint is 1.5

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Expand the expression, then solve for x.
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Answer:

5(2x+3)=25

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Which is the area of a circle with a diameter of 7 units? (use 3.14 for pi)​
Alex777 [14]

Answer:

The area of circle = πR ^2

And diameter = 7 units

By interchanging d in R =d/2 = R =7/2 = 3.5

Step-by-step explanation:

<h3>πR ^2 =3.14 x (3.5)^2</h3><h3> =3.14 x 3.5 x 3.5</h3><h3> =38.465 (unit)^2 <em><u>Answer</u></em></h3>

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3 years ago
Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3
Serhud [2]

Answer:

e^{3t}(2t+5t^{2})

Step-by-step explanation:

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem:L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]

Separate the fraction in a sum:

e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])

The formula for this is:

L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}

Modify the expression to match the formula.

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])

Solve

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )

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Answer:

answer is A. cosine

Step-by-step explanation:

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