It’s not a function because the domain (the X) is repeating...
X cannot repeat if you want it to be a function
The radius of the given circle is 5 units with the equation x²+y²+8x-6y+21=0.
<h3>
What are circles?</h3>
All points in a plane that are at a certain distance from the center combine to form a circle.
It is the curve that a moving point in a plane draws to keep its distance from another point constant, to put it another way.
In the center of a circle, equal chords subtend equal angles.
So, the radius of the circle with equation x² + y² + 8x – 6y + 21 = 0:
General form:
(x – a)² + (y-b) = r²
x² + y² – 2ax – 2by + (a² + b² – r²) = 0
We know that: r = √(a² +b²)
Compare the following equation to the equation's general form.
We obtain:
-2ax = 8x ⇒ a = – 4
-2by = -6y ⇒ b = 3
r = √((-4)2 +32 ) = √16 + 9 = √25 = 5
Therefore, the radius of the given circle is 5 units with the equation x²+y²+8x–6y+21=0.
Know more about circles here:
brainly.com/question/24375372
#SPJ4
Correct question:
What is the radius of a circle whose equation is x² + y² + 8x – 6y + 21 = 0?
90/3=30
30*4=120
120 calories in 4 cups with 30 calories in each cup.
-Steel jelly
Answer:
Step-by-step explanation:
Slope = y/x
y1-y2/x1-x2=slope of 2 points
8-3/-6-2 = 5/-8 which equals -5/8 or -.625.