Answer:
Where are the drop down menus ?
Step-by-step explanation:
is to say
for all
beyond some fixed
.
Similarly,
is to say
for all
.
From this we can gather that
where
is the larger of the two values
and
, or
. Then the last term is bounded above by
from which it follows that
The answer is HJ , just got 100 on the quiz :)
This questions stated differently so I’m assuming it’s 4?
1st number = n
2nd number = n+1
3rd number = n+2
sum of the squares of 3 consecutive numbers is 116
n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116 Last option.
