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zlopas [31]
3 years ago
10

HELP PLEASE 100 POINTS PLUS BRAINLIEST, (I had the answers already but some reason they got deleted

Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0

Answer:

\mathrm{11.\:}\frac{176}{5}\pi\:\mathrm{ft^2},\\\\\mathrm{12.\:}\frac{1573}{18}\pi\:\mathrm{mi^2},\\\\\mathrm{13.\:}\frac{269.08}{24}\pi\:\mathrm{km^2}\\\\\mathrm{14.\:}\frac{252.05}{6}\pi\:\mathrm{cm^2}\\\\\mathrm{15.\:}\frac{870.75}{72}\pi\:\mathrm{yd^2}\\\\\mathrm{16.\:}\frac{5953.48}{36}\pi\:\mathrm{m^2}

Step-by-step explanation:

The area of a sector can be given as:

\frac{c^{\circ}}{360^{\circ}}\cdot r^2\pi, where c is the angle of the sector in degrees.

<u>Problem 11:</u>

\frac{88^{\circ}}{360^{\circ}}\cdot 12^2\pi=\fbox{$\frac{176}{5}\pi\:\mathrm{ft^2}$}

<u>Problem 12:</u>

\frac{260^{\circ}}{360^{\circ}}\cdot 11^2\pi=\fbox{$\frac{1573}{18}\pi\:\mathrm{mi^2}$}

<u>Problem 13:</u>

Convert radians to degrees:

\frac{7\pi}{12}\cdot\frac{180}{\pi}=105^{\circ}

\frac{105^{\circ}}{360^{\circ}}\cdot 6.2^2\pi=\fbox{$\frac{269.08}{24}\pi\:\mathrm{km^2}$}

<u>Problem 14:</u>

Convert radians to degrees:

\frac{5\pi}{3}\cdot \frac{180}{\pi}=300^{\circ}

\frac{300^{\circ}}{360^{\circ}}\cdot 7.1^2\pi=\fbox{$\frac{252.05}{6}\pi\:\mathrm{cm^2}$}

<u>Problem 15:</u>

\frac{215^{\circ}}{360^{\circ}}\cdot 4.5^2\pi=\fbox{$\frac{870.75}{72}\pi\:\mathrm{yd^2}$}

<u>Problem 16:</u>

Convert radians to degrees:

\frac{13\pi}{18}\cdot\frac{180}{\pi}=130^{\circ}

\frac{130^{\circ}}{360^{\circ}}\cdot 21.4^2\pi=\fbox{$\frac{5953.48}{36}\pi\:\mathrm{m^2}$}

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Gary just started a new job as a nurse. he is given a starting salary of $58,550 per year. he is also told that his salary will
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Firts we need to find the rate of change, or in other words, the slope of the line.

Question 1:

a)

For this we can take two points in the form (years, salary). Then we can define as year 0 the year when Gary starts to work. In this year the salary is $58,550. The first point is (0, $58,550)

The next point we can take is at the year 10, when the salary of Gary will be $71,950. The second point is (10, $71,950)

b) Now that we have the two points, we can use the slope formula to get the rate of change. The slope formula is, for two points A and B:

\begin{gathered} \begin{cases}A(x_a,y_a) \\ B(x_b,y_b)\end{cases} \\ m=\frac{y_a-y_b}{x_a-x_b} \end{gathered}

In this case, we can call the points A(0, $58,550) and B(10, $71,950). Using the formula:

m=\frac{58,550-71,950}{0-10}=\frac{-13400}{-10}=1340

c) "The rate of change in Gary's salary is $1340 per year."

Question 2:

a) The slope intercept form of a line is:

y-y_1=m(x_{}-x_1)

Where:

y is the output of the function.

x is the input of the function. (we provide the function with a value for x and the function give us a value of y)

m is the slope of the line. We calculate it in question 1.

x1 is the x coordinate of a point we choose.

y1 is the y-coordinate of the same point of x1.

In this case, we know:

m = 1340;

And we can take the point (0, $58,550), thus:

x1 = 0

y1 = 58,550

b) Now we need to use all this values and use the slope-intercept form:

y-58,550=1340(x-0)

And solve to get:

y=1340x+58,550

Question 3:

a) Now we have a equation for the salary, we can use this to find the salary in 13 years. We just need to replace x = 13 in the equation:

\begin{gathered} \begin{cases}y=1340x+58,550 \\ x=13\end{cases} \\ y=1340\cdot13+58,550 \\ y=75,970 \end{gathered}

B) The salary of Gary in 13 years will be $75,970.

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