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3 years ago

Solve the simultaneous equation: 6x+4y=34 3x-y=14

Mathematics

1 answer:

Fantom [35]3 years ago

6 0

Answer:

x=5, y=1. (5, 1).

Step-by-step explanation:

6x+4y=34

3x-y=14

---------------

y=3x-14

6x+4(3x-14)=34

6x+12x-56=34

18x=34+56

18x=90

x=90/18

x=5

3(5)-y=14

15-y=14

y=15-14

y=1

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Step-by-step explanation:

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3 years ago

If the points below represent a direct variation, find the missing value (5,14)and (x,28)

bekas [8.4K]

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3 years ago

What is the mathematical answer for this matematicas question 5 1/5÷ 1/4

givi [52]

Answer:

Step-by-step explanation:

Convert mixed fraction to improper fraction. Then use KCF method

Keep the first fraction.

Change the division operation to multiplication.

Flip the second fraction

$5\frac{1}{5}=\frac{26}{5}$

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8 0

3 years ago

Read 2 more answers

The first term of an Ap is - 504 while<br>the sum of its 9 terms is-126 find<br>Sum of its 30 terms

frozen [14]

Answer:

The sum of its 30 terms is 38167.5

Step-by-step explanation:

Given:

The First term in the AP is -504

The Sum of its 9 terms is -126

To Find:

The sum of its 30 terms = ?

Solution:

The sum of n terms of an AP:

$S_n = (\frac{n}{2} ) [ 2 a_1 + ( n - 1 ) d ]$

The sum of 9 terms of an AP:

$S_9 = (\frac{9 }{2} ) [ 2(-504) + ( 9 - 1 )d ]$

$S_9 = (4.5 )[ 2 (-504)+ ( 8 ) d ]$

$(4.5 )(2)(-504) + (4.5) 8 d = - 126$

(-4536) +36d = -126

36 d = -126+4536

36 d= 4410

$d= \frac{4410}{36}$

d = 122.5

The sum of its 30 terms is

$S_{30} = ( \frac{30 }{2 }) [ 2 (-504) + ( 30-1)(122.5) ]$

$S_{30} =(15) [ 2 (-504) + ( 29)(122.5) ]$

$S_{30} = [ 2 (-504)(15) + ( 29)(122.5)(15) ]$

$S_{30} = [ -15120 + 53287.5 ]$

$s_{30} = 38.167.5$

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4 years ago