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Vika [28.1K]
2 years ago
5

What is the value of point H on the number line? A. 3/5 B. 2.6 C. 5/3 D. 1.4

Mathematics
2 answers:
mario62 [17]2 years ago
8 0
I believe that it’s D
Basile [38]2 years ago
8 0
Hi the answer is b. 2.6
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What are the values of x and y? I REALLY NEED Y , I HAVE X. I will mark you brainliest if you give me y and its correct!​
Mazyrski [523]

Answer:

72.5°

Step-by-step explanation:

180° - 35° = 2y°

145° = 2y

145/2 = 50+22+0.5 = 72.5

4 0
3 years ago
A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The
zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200,  300

Let X be the total refund payment on the seven day cruise.

We can say  X = 0, if there is no rain on all 7 days.

P(X = 0) = _nC_x * P^x * (1 - P)n-x

P(X = 0) =  _7C_o * 0.2^0 * (1-0.2)^{7-0

P(X = 0) =1 * 1* (1-0.2)^{7

P(X = 0) =(0.8)^{7

P(X = 0) =0.2097152

If it rains on any one day; then X = 100

P(X = 100) = _nC_x * P^x * (1 - P)n-x

P(X = 100) =  _7C_1 * 0.2^1 * (1-0.2)^{7-1

P(X = 0) =7 * 0.2* (1-0.2)^{6

P(X = 100) =7* 0.2* (0.8)^{6

P(X = 100) =0.3670016

if it rains on any two day  ; then X = 200

P(X = 200) = _nC_x * P^x * (1 - P)n-x

P(X = 200) =  _7C_2 * 0.2^2 * (1-0.2)^{7-2

P(X = 200) =  21 * 0.2^2 * (0.8)^{5

P(X = 200) = 0.2752512

if it rains on any three day or more than that ; then X = 300

P(X \ge 300) = 1 - P(X < 300)  \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple[Var X] =E [X^2] - (E [X])^2

where;

E[X^2]  = \sum x^2 \times p \\ \\ E[X^2]  = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\  E[X^2]  = 0  + 3670.016 + 11010.048+ 13322.88  \\ \\  E[X^2]  =28002.944

(E [X]) = \sum x * p\\ \\  (E [X]) =  0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0
3 years ago
Jayne stopped to get gas before going on a road trip. The tank already had 4 gallons of gas in it. Which of the statements below
Juli2301 [7.4K]
A. The graph will be continuous because the amount of gas that she added to the tank does not need to be an integer amount.
4 0
3 years ago
Read 2 more answers
In a random sample of 75 American women age 18 to 30, 26 agreed with the statement that a woman should have the right to a legal
ddd [48]

Answer:

a) z=\frac{0.347-0.328}{\sqrt{0.338(1-0.338)(\frac{1}{75}+\frac{1}{64})}}=0.236  

p_v =2*P(Z>0.236)=0.813  

If we compare the p value and using any significance level for example \alpha=0.01 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant differences between the two proportions.  

b) We are confident at 99% that the difference between the two proportions is between -0.188 \leq p_B -p_A \leq 0.226

Step-by-step explanation:

Previous concepts and data given

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion of women age 18 to 30  agreed with the statement that a woman should have the right to a legal abortion for any reason

\hat p_A =\frac{26}{75}=0.347 represent the estimated proportion of women age 18 to 30  agreed with the statement that a woman should have the right to a legal abortion for any reason

n_A=75 is the sample size for A

p_B represent the real population proportion for women age 58 to 70  agreed with the statement that a woman should have the right to a legal abortion for any reason

\hat p_B =\frac{21}{64}=0.328 represent the estimated proportion of women age 58 to 70  agreed with the statement that a woman should have the right to a legal abortion for any reason

n_B=64 is the sample size required for B

z represent the critical value for the margin of error and for the statisitc

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part a

We need to conduct a hypothesis in order to check if the proportion are equal, the system of hypothesis would be:  

Null hypothesis:p_{A} = p_{B}  

Alternative hypothesis:p_{A} \neq p_{B}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{A}-p_{B}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{A}}+\frac{1}{n_{B}})}}   (1)

Where \hat p=\frac{X_{A}+X_{B}}{n_{A}+n_{B}}=\frac{26+21}{75+64}=0.338

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.347-0.328}{\sqrt{0.338(1-0.338)(\frac{1}{75}+\frac{1}{64})}}=0.236  

Statistical decision

Since is a two sided test the p value would be:  

p_v =2*P(Z>0.236)=0.813  

If we compare the p value and using any significance level for example \alpha=0.01 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant differences between the two proportions.  

Part b  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.58  

And replacing into the confidence interval formula we got:  

(0.347-0.328) - 2.58 \sqrt{\frac{0.347(1-0.347)}{75} +\frac{0.328(1-0.328)}{64}}=-0.188  

(0.347-0.328) + 2.58 \sqrt{\frac{0.347(1-0.347)}{75} +\frac{0.328(1-0.328)}{64}}=0.226  

And the 99% confidence interval for the difference of proportions would be given (-0.188;0.226).  

We are confident at 99% that the difference between the two proportions is between -0.188 \leq p_B -p_A \leq 0.226

5 0
3 years ago
Qual é o mdc de 340 e 728?
Diano4ka-milaya [45]
MDC and largest number that can divide two numbers while 
<span>340.728 2 </span>
<span>170.364 2 </span>
<span>85 182  </span>
<span>the highest numeropossivel that can divide two numbers are the same times 4 = 2.2</span>
7 0
3 years ago
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