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Dmitrij [34]
3 years ago
11

Write an equation in point slope form of the line that passes through the point (2,-8) and had a slope of 4

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0
Point slope: y - y1 = m(x - x1)
Plug those in
Solution: y + 8 = 4(x - 2)
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A. thirty-five degrees
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1 Subtracting Fractions
antoniya [11.8K]

Step-by-step explanation:

The question is not properly structured but we can as well find the sum of 5/7 and 10 as shown;

\frac{5}{7}+ \frac{10}{1} \\The \ LCM \ is \ 7\\\\= \frac{5(1)+10(7)}{7}\\\\=   \frac{5+70}{7}\\\\= \frac{75}{7}  \\\\= 10 \frac{5}{7}

Hence the expression written in equivalent form of common denominator is \frac{5 + 70}{7}

The sum is 10 \frac{5}{7}

8 0
3 years ago
Express 610.47 in unit form.
Annette [7]

Answer:

6 hundreds

1 tens

0 ones

4 tenths

7 hundredths

8 0
4 years ago
Find the simple interest rate needed in order for an investment of $2000 to grow to an account of $5000 in 3 years
Nutka1998 [239]

\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$5000\\ P=\textit{original amount deposited}\dotfill&\$2000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &3 \end{cases} \\\\\\ 5000=2000(1+r3)\implies \cfrac{5000}{2000}=1+3r\implies \cfrac{5}{2}=1+3r \\\\\\ 5=2+6r\implies 3=6r\implies \cfrac{3}{6}=r\implies 0.5=r\implies \stackrel{\textit{converting to percent}}{0.5\cdot 100\implies 50\%}

5 0
4 years ago
a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
3 years ago
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