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irina1246 [14]
4 years ago
8

Find the simple interest rate needed in order for an investment of $2000 to grow to an account of $5000 in 3 years

Mathematics
1 answer:
Nutka1998 [239]4 years ago
5 0

\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$5000\\ P=\textit{original amount deposited}\dotfill&\$2000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &3 \end{cases} \\\\\\ 5000=2000(1+r3)\implies \cfrac{5000}{2000}=1+3r\implies \cfrac{5}{2}=1+3r \\\\\\ 5=2+6r\implies 3=6r\implies \cfrac{3}{6}=r\implies 0.5=r\implies \stackrel{\textit{converting to percent}}{0.5\cdot 100\implies 50\%}

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Calculate the mean of the following list of numbers: 3, 5, 2, 10, 6, 3, 7, 3
BabaBlast [244]

Answer:

4.875

Step-by-step explanation:

The mean is the average of all the numbers or all the numbers added up divided by how many numbers so

3+5+2+10+6+3+7+3=39 and there are 8 numbers so

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4.875

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there are about 290 kids in a school. if there are 14 teachers and 5 subs how many kids would be in a class with teachers and su
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If there is 290 kids,14 teachers, and 5 subs the you have to do adding
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4 years ago
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Roman55 [17]

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Each friend got 2 apples

Step-by-step explanation:

[original amount of apples]-[Apples Sally has after distribution] = [friends] x [number of apples]

Filling in the brackets, you get this equation.

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3 years ago
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sana is senior to Mona by 18 years after 6 years.Sana will be twice as old as Mona. find Mona,s percentage​
Gwar [14]
Let
Present age of Sana = s
Present age of Mona = m


Sana is senior to Mona by 18 years
s=m+18............(1)

After 6 years
Sana will be = s+6
Mona will be = m+6
Then
Sana will be twice as old as Mona
(s+6)=2(m+6)
s+6=2m+12
s=2m+12-6
s=2m+6.............(2)
Put the value of s from (2) to (1)
2m+6=m+18
2m-m=18-6
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Put the value of m in (1)
s=m+18
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Present age of Sana = s = 30 years old
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3 0
3 years ago
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yawa3891 [41]

Answer:

10

Step-by-step explanation:

just try to make the lines even and get the answer 10

7 0
3 years ago
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