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katrin [286]
3 years ago
12

6.34 1.645 10.3401-0.34 45

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Step-by-step explanation:

dude wut r we suppose to do??

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(2x+3y) + (5x+3y) = 4 +-8
Artist 52 [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
HELP!
Harlamova29_29 [7]

Answer:

2/8 or 1/4

Step-by-step explanation:

2/8 or 1/4 because the spots on the spinner are blue out of 8 is 2/8 or 1/4

3 0
3 years ago
There are two consecutive positive even integers such that the square of the first is 364 more than five times the second. What
xxMikexx [17]

Answer:

Step-by-step explanation:

There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?

Two consecutive year positive integers are represented by

x and x + 1

First integer = x

Second integer = y

There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.

This is represented mathematically as:

x² = 364 + 5(x + 1)

x² = 364 + 5x + 5

x² -5x -5 - 364

x² - 5x - 369

6 0
3 years ago
Lily took out a 5-year loan from the bank for $31,000 to purchase a new car. At the end of the loan, she had paid a total of $37
otez555 [7]

Answer:

=24.5%

Step-by-step explanation:

  1. Simple interest = (principal×rate×time)÷100. *brackets first*
  2. transpose the formula to make rate the subject: rate= (100×simple interest) ÷ (principal×time)
  3. plug in values: rate = (100×37975) ÷ (31000×5)
  4. the result is 24.5%
8 0
3 years ago
Find the radius of the circle with equation x²+y²+8x+8y+28=0
galina1969 [7]
<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^{2}+y^{2}+8x+8y+28=0

So, solving we have:

x^{2}+y^{2}+8x+8y=-28

(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4

(x^2-(-4))+(y^2-(-4))=4

Now, we have that:

h=-4\\k=-4\\r=\sqrt{4}=2

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0
3 years ago
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