Answer:
0.0417
Step-by-step explanation:
Given the following;
p = 0.7, n=121
The sampling distribution of sample proportion will be approximately normal with mean
\mu_{\hat{p}}=p=0.7
and standard deviation
\sigma_{\hat{p}}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7\cdot 0.2}{121}}=0.0417
Check attachment for the curve diagram.
Change the equation to slope intercept form:
-5y=-x+10
y=1/5x-2
The y intercept is -2
Answer:
Since there are 4 green bars for every 3 red bars and we are trying to find the number of red bars if there are 200 green bars, we can create the ratio:
4
x
:
3
y
Where x is equal to the number of green bars and y
is the number of red bars.
We know the number of green bars is equal to 200, so we can divide it by 4, giving us:
200
/4=50
Then we can solve for y
, the number of red bars.
// Multiple y by 50
3
⋅
50
=
150
So for every 4 green bars, there are 3 red bars.
For every 200 green bars, there are 150 red bars
Step-by-step explanation:
The correct answer is C. F(x)=2 * (0.7)^x
Answer:
0.5372
Step-by-step explanation:
Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.
Let X be the no of births in the hospital per hour
X is Poisson
with mean = 1.8
the probability of observing at least two births in a given hour at the hospital
= 
the probability of observing at least two births in a given hour at the hospital = 0.5372