Answer:
0.0417
Step-by-step explanation:
Given the following;
p = 0.7, n=121
The sampling distribution of sample proportion will be approximately normal with mean
\mu_{\hat{p}}=p=0.7
and standard deviation
\sigma_{\hat{p}}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7\cdot 0.2}{121}}=0.0417
Check attachment for the curve diagram.
Answer:
0.5372
Step-by-step explanation:
Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.
Let X be the no of births in the hospital per hour
X is Poisson
with mean = 1.8
the probability of observing at least two births in a given hour at the hospital
=
the probability of observing at least two births in a given hour at the hospital = 0.5372